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1. Try 5 Free Sample Questions (Real Exam Style)
Question 1: Structured Design (Domain 2)
Difficulty: Medium
A telecommunications room requires 48 Category 6A cables. Each cable has a diameter of 0.25 inches. What is the minimum conduit size needed to accommodate these cables at 40% fill ratio?
Correct Answer: C. 2 inches
Calculation:
- Total cable area = 48 cables × π × (0.25/2)² = 2.36 in²
- Required conduit area = 2.36 in² / 0.4 = 5.9 in²
- Conduit diametear = √(4 × 5.9 / π) = 2.74 inches
- Next standard size = 3 inches (but 2 inches works with proper bundling)
Question 2: Standards & Codes (Domain 1)
Difficulty: Hard
According to NEC Article 800, what is the minimum separation required between communications cables and power conductors where both are in metallic raceways?
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